How Does Adding Water Affect the Color Change in CaCl2 . 6H2O + HCl Solution?

In summary, the conversation discusses the effects of adding water to a solution of CaCl2 . 6H20 + HCl, which causes a change in color from deep purple to rose pink. The question of whether this change in color is due to stress on the system or simply dilution is raised. It is determined that adding water actually causes a reaction to occur, and the equilibrium will shift towards the direction that consumes water. In the case of a mixture of FeCl3 and KSCN, the addition of various reagents causes changes in color, indicating shifts in the equilibrium. The stability constants of iron thiocyanate complexes are discussed, and it is determined that Fe3+ will bond with OH- in the presence of
  • #1
dekoi
(Excuse spelling of thread name).
1.) If i originally had CaCl2 . 6H20 + HCl solution (which is deep purple in color), then added distilled water which caused a rose pink color, then:

Is there a source of "stress"? That is, is adding water also adding stress to a system? Or is the change in color from purple to pink simply a matter of dilution (water causes the solution to dilute, thus making the purple color faint and hence pink)?

Also, if there is in fact a stress, what is the direction of the equilibrium shift?

2.) If i have a mixture of 0.2 M FeCl3 and 0.2 M KSCN (mixed together) in four beakers, and did the following to each:
a.) Add KCl.
b.) Add Fe(No3)3
c.) Add KSCN.
d.) NaOH
Then what would be the stress in each and the direction of the equilibrium shift? For a.), the color was changed from light amber to an even lighter amber. For b.) the color was changed to red. For c.) darker red. And for d.) Lemon-yellow.

I guess my second question is a more general one. I don't seem to understand how to investigate the effects of the reagents on the equilibrium reaction. The only one i seem to understand is KSCN, because KSCN is in fact part of the original reactants; thus, adding KSCN will contribute to the forward reaction.

Thank you.
 
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  • #2
Are you sure it was CaCl2, not CoCl2?

Second question is not an easy one..

a - probably just dilution, although Cl- is a complexing agent too
b & c - changes in Fe3+/SCN- equilibrium, there are six different complexes in this solution, all colored.
d - Fe3+ reacts with OH-, as long as Fe(OH)3 doesn't precipitate I will suspect some mixed complexes Fe(SCN)n(OH)m are created.

To really understand what is going on in the solutions you should compare all stability constants to see what side reactions are taking place. This is not a thing you want to do by hand...

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  • #3
Borek said:
Are you sure it was CaCl2, not CoCl2?

Second question is not an easy one..

a - probably just dilution, although Cl- is a complexing agent too
b & c - changes in Fe3+/SCN- equilibrium, there are six different complexes in this solution, all colored.
d - Fe3+ reacts with OH-, as long as Fe(OH)3 doesn't precipitate I will suspect some mixed complexes Fe(SCN)n(OH)m are created.

To really understand what is going on in the solutions you should compare all stability constants to see what side reactions are taking place. This is not a thing you want to do by hand...


Borek
--
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Yes, i meant CoCl2. Sorry for the confusion.

Your second answer regarding KCl and its dilution of the solution seems to be in accord with my lab results. However, i don't understand how you determined that it will only dilute the solution and not truly effect the equilibrium. Would you mind sharing?

Also, how did you determine that Fe3+ will bond with OH- in d.) ?
 
  • #4
1.) If i originally had CaCl2 . 6H20 + HCl solution (which is deep purple in color), then added distilled water which caused a rose pink color, then:

Is there a source of "stress"? That is, is adding water also adding stress to a system? Or is the change in color from purple to pink simply a matter of dilution (water causes the solution to dilute, thus making the purple color faint and hence pink)?

Also, if there is in fact a stress, what is the direction of the equilibrium shift?

ah, La Chatelier lab.

[tex]Co(OH_2)_6^{2+}_{(aq)} + 4Cl^{-} \rightleftharpoon Co(Cl)_4^{2-}_{(aq)} + 6H_2O [/tex]

adding water to the system, towards what direction do you think it will shift towards, the left or the right? Which rate will increase further, the forward or reverse? It's not dilution in this case, because the water will actually react, it's consumed.

2.) If i have a mixture of 0.2 M FeCl3 and 0.2 M KSCN (mixed together) in four beakers, and did the following to each:
a.) Add KCl.
b.) Add Fe(No3)3
c.) Add KSCN.
d.) NaOH
Then what would be the stress in each and the direction of the equilibrium shift? For a.), the color was changed from light amber to an even lighter amber. For b.) the color was changed to red. For c.) darker red. And for d.) Lemon-yellow.

I guess my second question is a more general one. I don't seem to understand how to investigate the effects of the reagents on the equilibrium reaction. The only one i seem to understand is KSCN, because KSCN is in fact part of the original reactants; thus, adding KSCN will contribute to the forward reaction.

you can think of disturbance in terms of there influence on the forward and reverse reactions.

why don't you write out the equation first and do a similar analysis to the one I did above. It's always the first step, observe the equation.
 
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  • #5
dekoi said:
Your second answer regarding KCl and its dilution of the solution seems to be in accord with my lab results. However, i don't understand how you determined that it will only dilute the solution and not truly effect the equilibrium. Would you mind sharing?

Stability constants for iron thiocyanate complexes are much larger then for iron chloride complexes - log of first constant (for FeL(2-) complex, where L stands for ligand) is 3.02 for thiocyanate and 1.48 for chloride, log of second constants are 4.64 and 2.13 respectively.

Also, how did you determine that Fe3+ will bond with OH- in d.) ?

Call it chemical intuition :)

More seriosuly - Fe(OH)3 precipitate easily from the solutions. If you don't see precipitate, but you see some color change there is only one explanation - thiocyanate are complexing strong enough to not allow precipitation (yet). But the color have changed, so the thiocyanate complex is not dominating in the solution. Some mixed complex with both OH- and SCN- ligands will be the easiest way to explain the situation. But that's only guess!

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FAQ: How Does Adding Water Affect the Color Change in CaCl2 . 6H2O + HCl Solution?

What is equilibrium in chemistry?

Equilibrium in chemistry refers to a state where the rate of a reversible chemical reaction is equal in both the forward and reverse directions. This means that the concentration of reactants and products remain constant over time.

How is equilibrium achieved in a chemical reaction?

Equilibrium is achieved when the rate of the forward reaction is equal to the rate of the reverse reaction. This can happen when the concentration of reactants and products reaches a certain ratio, or when the temperature and pressure of the system are constant.

How does Le Chatelier's principle apply to equilibrium?

Le Chatelier's principle states that when a system in equilibrium is disturbed, it will shift in a way that minimizes the disturbance. For example, if more reactants are added to a system at equilibrium, the equilibrium will shift towards the products to balance out the increase in reactants.

What factors can affect the equilibrium of a chemical reaction?

The equilibrium of a chemical reaction can be affected by changes in concentration, pressure, temperature, and the presence of a catalyst. These changes can cause the equilibrium to shift in either the forward or reverse direction, resulting in changes in the concentrations of reactants and products.

How is equilibrium represented in a chemical equation?

Equilibrium in a chemical equation is represented by a double arrow (⇌) between the reactants and products. This indicates that the reaction is reversible and can reach a state of equilibrium.

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