How Does an E Baryon Decay into a D Baryon and a Photon?

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An E baryon with an energy of 2 GeV decays into a D baryon and a photon through electromagnetic interactions. In the lab frame, the decay is visualized with the photon and D baryon emitted at a 90-degree angle. In the rest frame of the E baryon, the photon and D baryon approach each other with equal and opposite momentum, forming a 180-degree angle. For the D baryon to achieve maximum energy, it must have equal and opposite momentum to the photon. There is a noted lack of references for the rest masses of D and E baryons, raising questions about the decay dynamics.
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An E baryon, traveling with an energy of 2 GeV, decays electromagnetically into a D baryon and a photon.

Sketch how this decay might appear in the general case
(i) in the lab frame
E D
A. Essentially I assume you will have ----> <
photon
(with the photon and D coming off that with a 90 degree angle between them.

(ii) in the rest frame of the E baryon.

A.
Photon D
------> E <------ The photon approaching each other with equal and opposite momentum.

What conditions are necessary for D to have maximum energy.

A. D must have equal and opposite momenta to the photon.
 
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I can't find any references for D baryons and E baryons. Do you have rest masses for these? I'm not seeing why there has to be a 90° angle in the lab frame. In the rest frame of the E Baryon the D baryon and the photon must have 180° angle between them.
 
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