How Does Archimedes' Principle Determine Buoyant Force?

[skandol]

Achimedes' Prinicple! HELP

Homework Statement

A rock has a volume of 5.96x10-6 m3. When it is completely submerged in a beaker of water, the water exerts a buoyant force on the rock equal to ___ Newtons.

Homework Equations

Kind of confused...

d=m/v

B= densityofwater (voulme)

is that correct?

 

[mgb_phys]

The force is equal to the weight of water displaced
How much does 5.96x10-6 m3 of water weigh?

 

[nlightner]

Yes, your equation for density (d=m/v) is correct. However, to solve this problem, you will also need to use Archimedes' Principle, which states that the buoyant force on an object is equal to the weight of the fluid it displaces. So, in this case, the buoyant force on the rock will be equal to the weight of the water that the rock displaces. You can calculate the weight of the water by using its density (which is typically given in kg/m^3) and multiplying it by the volume of water displaced by the rock. Once you have the weight of the water, you can convert it to Newtons using the conversion factor 1N = 1kg*m/s^2. I hope this helps! Let me know if you have any further questions.