- #1
Elmowgli
- 6
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Hi, I am a little stuck on this question from a PPOD paper I am doing all help appreciated =)
A solid circular disc of mass 6.6kg and radius 0.25m rotates about an axis which coincides with its diamter. Its angular acceleration is found to be 6.7rad/s. The axis of rotation is changed so that it lies 0.15m from the centre of the disc, and is parallel to the diameter. If the applied moment is the same, determine the angular acceleration.
I=mR^2/4
I=rα
ive worked out the moment of inertia of the disc before the axis is changed and get
I = 0.103kgm^2
I was wondering if the next step is simple to use I=rα and use 0.15 as the value for the radius or should I use the parallel axis theorem as the axis has changed from being perpendicular to parallel??
Homework Statement
A solid circular disc of mass 6.6kg and radius 0.25m rotates about an axis which coincides with its diamter. Its angular acceleration is found to be 6.7rad/s. The axis of rotation is changed so that it lies 0.15m from the centre of the disc, and is parallel to the diameter. If the applied moment is the same, determine the angular acceleration.
Homework Equations
I=mR^2/4
I=rα
The Attempt at a Solution
ive worked out the moment of inertia of the disc before the axis is changed and get
I = 0.103kgm^2
I was wondering if the next step is simple to use I=rα and use 0.15 as the value for the radius or should I use the parallel axis theorem as the axis has changed from being perpendicular to parallel??