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foxcub156
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Homework Statement
A bead with mass (1.8x10^-2)kg is moving along a wire in the positive direction of an x axis. Beginning at time=0, when the bead passes through x=0 with speed 12m/s, a constant force acts on the bead, the picture indicates the bead's position at these four times: t0=0 sec., t1=1.0 sec., t2=2.0 sec., t3=3.0 sec., The bead momentarily stops at t=3.0 sec. What's the kinetic energy of the bead as t=10 sec?
Homework Equations
K=(.5)mv^2
vf^2=vi^2+2ad
The Attempt at a Solution
Is the answer K=1.296? I really think it's wrong.