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ScienceChem
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Homework Statement
A hydraulic fluid initially at 60◦C is cooled to 35◦C using a co-current heat exchanger. Cooling water is available at 15◦C, which must not exceed 30◦C on leaving the heat exchanger. The flow rate of the hydraulic fluid is 1.5 kg/s, which has a specific heat of 5.2 J/gํ C. Calculate the heat to be removed from the hydraulic fluid and the area required for the heat exchanger. Assume no fouling takes place. U = 520 W/m2°C
Homework Equations
Co-current heat exchanger: LMTD = {(Ti-ti)-(To-to)} / ln{(Ti-ti)/(To-to)}
Ti = temp of cooling / heating water in
ti = temp of liquid to be cooled / heated in
The Attempt at a Solution
I have no idea where to begin with this!