- #1
lilaznjewel
- 13
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Homework Statement
Given: A flat dance floor of dimensions ℓx =
19 m by ℓy = 23 m and has a mass of M =
1600 kg. Use the bottom left corner of the
dance floor as the origin. Three dance couples,
each of mass m = 150 kg start in the top left,
top right, and bottom left corners.
What is the initial y coordinate of the cen-
ter of gravity of the dance floor and three
couples?
Answer in units of m.
The couple in the bottom left corner moves
ℓx = 10 m to the right. What is the new x
coordinate of the center of gravity?
Homework Equations
xcm =
m1x1 + m2x2/
m1 + m2
The Attempt at a Solution
for the first part I did 1600(y-11.5)+150(y-23)+150(y-0)+150(y-23)=0
and solved for y and I got 12.34
and I got it right
my problem is I did the exact same thing for the next part just you know used the X coordinates and moved (0,0) to (10,0)
1600(x-8)+150(x-0)+150(x-10)+150(x-19)=0
I came out with 8.366
but my online homework says that answer is incorrect I don't know why isn't it basically the same question but with a different number