- #1
yucheng
- 232
- 57
- Homework Statement
- Understand the Galvanic Cell, and not let it insult your intelligence
- Relevant Equations
- N/A
I was watching this video that I found on Youtube.
My question is, does type of electrolyte affect the voltage reading, since it dictates which redox reactions are possible? (here, Na2SO4 instread of CuSO4)
Consider a Mg|Cu electrode pair in a galvanic cell; the reaction is, usually in textbooks, between ##\text{Mg}|\text{Cu}^{2+}##, where Cu electrode can, in this reaction, be considered inert. Hence, the voltage measured is actually between ##\text{Mg}|\text{Cu}^{2+}## (with all the salt bride/porous pot), right?
So, does the voltage between Mg|Cu electrode pair with Na2SO4 electrolyte mean? It is not the potential difference calculated from the ##E^0## value of half cell equations of Mg and Cu.
Also,
If you connect 2 different metals with a wire (with no electrolyte), will there still be a natural flow of electrons, albeit only to a small degree?
https://www.quora.com/If-you-connec...ow-of-electrons-albeit-only-to-a-small-degree
But after a flow of electrons, won't the potential difference then become 0? Plus, does this have anything to do with the ##E^0## in the of standard electrode potential (see my argument above about Mg|Cu vs Mg|Cu2+)?
P.S. I am still confused with what actually gives rise to the voltage!
My question is, does type of electrolyte affect the voltage reading, since it dictates which redox reactions are possible? (here, Na2SO4 instread of CuSO4)
Consider a Mg|Cu electrode pair in a galvanic cell; the reaction is, usually in textbooks, between ##\text{Mg}|\text{Cu}^{2+}##, where Cu electrode can, in this reaction, be considered inert. Hence, the voltage measured is actually between ##\text{Mg}|\text{Cu}^{2+}## (with all the salt bride/porous pot), right?
So, does the voltage between Mg|Cu electrode pair with Na2SO4 electrolyte mean? It is not the potential difference calculated from the ##E^0## value of half cell equations of Mg and Cu.
Also,
If you connect 2 different metals with a wire (with no electrolyte), will there still be a natural flow of electrons, albeit only to a small degree?
https://www.quora.com/If-you-connec...ow-of-electrons-albeit-only-to-a-small-degree
But after a flow of electrons, won't the potential difference then become 0? Plus, does this have anything to do with the ##E^0## in the of standard electrode potential (see my argument above about Mg|Cu vs Mg|Cu2+)?
P.S. I am still confused with what actually gives rise to the voltage!
Last edited: