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Homework Statement
An electron has a de Broglie wavelength equal to the diameter of a hydrogen atom in its ground state.
What is the kinetic energy of the electron?
How does this energy compare with the ground-state energy of the hydrogen atom?
Homework Equations
λ = h /mv
diameter = 2 x bohr radius = 1.06e-10 m
The Attempt at a Solution
1.06e-10 = 6.63e-34/1.67e-27v
v = 3.75e3 m/s
.5(1.67e-27)(3.75e3)^2 = 1.17e-20 J = .0732 eV
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.