- #1
paton51
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Im trying to model a car going round a corner and the speed at which it will overturn (assuming no slip)
Is it correct that when turning there are lateral friction forces that oppose the inertial 'centrifugal' force? i.e. towards the centre of curvature
When the front (driving) wheel are turned at an angle does this force still act perpendicular to the direction of the wheel?
Also, how much effect would there be from friction resisting the direction of travel?
and i know that the friction on a 'non driven' wheel opposes the direction of travel but, is it opposite for a 'driving' wheel?
Any help would be appreciated
Thanks
Is it correct that when turning there are lateral friction forces that oppose the inertial 'centrifugal' force? i.e. towards the centre of curvature
When the front (driving) wheel are turned at an angle does this force still act perpendicular to the direction of the wheel?
Also, how much effect would there be from friction resisting the direction of travel?
and i know that the friction on a 'non driven' wheel opposes the direction of travel but, is it opposite for a 'driving' wheel?
Any help would be appreciated
Thanks