How Does Gauss's Law Apply to Oscillating Bars in an Electrical System?

In summary, the two 30cm bars with a resistance of 2-ohms each are connected to a 1,500 volt battery and attached to each other with 3 insulating springs. When the switch is closed, the bars are 4cm apart. After the switch is open, the bars will experience harmonic oscillation with an amplitude of 4 cm and a period determined by the equivalent spring constant of 27N/m. The closest they will get to each other is 0 cm and the farthest they will get is 8 cm. There is no friction in the system.
  • #1
Turpulus
11
0
Question about Gauss flux??

Homework Statement


Two bars, each 30cm long, and each having a resistance of 2-ohms, are connected to a 1,500 volt battery. The bars are attached to each other with 3 insulating springs, each having a spring constant of 9N/m. The two bars are initially at rest, 4cm apart. The switch is closed, and then opened. Assume no friction anywhere in the system. 1. How far will the two bars be from each other with the switch is closed? 2. After the switch is open, what is the closest the two bars wil get to each other? 3. After the switch is open, what is the farthest the two bars will get from each other? 4. Describe the motion of the two bars at time, t, after the switch is open.



The Attempt at a Solution


I was able to find the equivalent spring constant of 27N/m since there are 3 springs. After that, I just don't know how to proceed. I think it's supposed to deal with Gauss Flux. If anyone can give me any advice on how to tackle this one it would be much appreciated. Thanks!
 
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  • #2
Answer: 1. The two bars will be 4cm apart when the switch is closed. 2. The closest the two bars will get to each other is 0 cm once the switch is open. 3. The farthest the two bars will get from each other is 8 cm once the switch is open. 4. The motion of the two bars at time t after the switch is open can be described as a harmonic oscillation. The bars will move towards and away from each other with an amplitude of 4 cm and a period determined by the equivalent spring constant of 27N/m.
 

FAQ: How Does Gauss's Law Apply to Oscillating Bars in an Electrical System?

What is Gauss flux?

Gauss flux, also known as Gaussian flux or Gaussian surface flux, is a physical quantity used in electromagnetism to measure the amount of electric or magnetic field passing through a given area or surface.

How is Gauss flux calculated?

Gauss flux is calculated by taking the integral of the electric or magnetic field over a closed surface. Mathematically, it can be represented as Φ = ∫∫E*dA or Φ = ∫∫B*dA, where E is the electric field, B is the magnetic field, and dA is the differential area element.

What is the unit of Gauss flux?

The unit of Gauss flux depends on the unit of the electric or magnetic field being integrated. For electric field, it is measured in volts (V) or newtons per coulomb (N/C). For magnetic field, it is measured in webers (Wb) or teslas (T).

Why is Gauss flux important?

Gauss flux is important because it helps us understand and quantify the behavior of electric and magnetic fields. It is used in many practical applications, such as in engineering and physics, to analyze and design systems involving electric or magnetic fields.

How is Gauss flux related to Gauss's law?

Gauss flux is closely related to Gauss's law, which states that the total electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of free space. This allows us to use Gauss flux to calculate the electric field at a point due to a known charge distribution.

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