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Homework Statement
An open jar of water moves in a vertical circle of radius ##0.50m## with a frequency that is small enough to put the water on the verge of falling out of the jar at the top of to the circle.If the same demonstration were repeated on Mars,where the ##a_g## is only ##3.7 \frac {m} {s^2}## ,what is the change in the circling frequency to again put the water on the verge of falling out at the top point.
Homework Equations
##a_r=\frac {v^2} {r}##
##v=2πfr##
The Attempt at a Solution
##a_r=\frac {v^2} {r}##
##v=2πfr##
##m\frac {v^2} {r}=mg##
from these
I found ##0.27 Hz##, which its correct.But there's something that I confused.
##m\frac {v^2} {r}=mg## how can these can be equal..weight must point downward and the other force is pointing inward...? I didnt quite understand the logic..I tried to understand but I couldnt
Thanks