- #1
jrk613
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Homework Statement
A 4.94 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 12.1 N at an angle θ = 15.0° above the horizontal, as shown in the Figure.
The coefficient of kinetic friction between the block and the floor is 0.100. What is the speed of the block 3.70 s after it starts moving?
Homework Equations
F=ma
The Attempt at a Solution
I understand to find the acceleration I need F=ma, so cos(15)12.1 = 4.94(a).
And I know that when I find the (a), I can just * the 3.7 seconds. I just don't know where to fit in the kinetic friction of 0.1. I'm guessing it has to be minus from the total F but something isn't going right, any ideas, thanks