How Does Kirchhoff's Law Apply to Calculating Currents and Voltage Differences?

  • Thread starter flyingpig
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In summary: I can see how it would be easier if the currents were confined to the same loop, but I can't help but feel that there must be a more elegant way to do this.In summary, the two loops have two resistances in common (4Ω), but the currents are still separate.
  • #36
For the same reason that any other wrong answer is wrong.

There is no reason the answer should be 12V - 8V.
 
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  • #37
But was my guess at what the answer really should have been right when you hinted at me? That it is the voltage drop across the 2Ω resistor because the 2Ω resistor is the only resistor in the intersection of the loop?
 
  • #38
flyingpig said:
But was my guess at what the answer really should have been right when you hinted at me? That it is the voltage drop across the 2Ω resistor because the 2Ω resistor is the only resistor in the intersection of the loop?
Yes.

As long as you got Ia & Ib right.
 
  • #39
Sammy, the solutions posted said the voltage drop is -1.80V

Here is my question, when we tackle these problems, aren't we only concerned with the magnitude?
 
  • #40
flyingpig said:
Sammy, the solutions posted said the voltage drop is -1.80V

Here is my question, when we tackle these problems, aren't we only concerned with the magnitude?

No. Among other things, the sign has to do with which way the current flows.
 
  • #41
Then how do I know that it is -1.80V?
 
  • #42
The sign will depend upon whether they found Va - Vb or Vb - Va.
 
  • #43
So it is not unique?
 

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