How Does Light Reach Bob in Special Relativity?

In summary, the conversation discusses the problem of determining at what time the light from a lamp reaches Bob, who is moving in frame S0 with a speed of v, as observed by Andrew in frame S. Two attempts are made at solving the problem, with the first attempt using the equation Δt'=γΔt and the second attempt considering the relativity of simultaneity. The first attempt is determined to be correct, while the second attempt fails to account for the relativity of simultaneity. Finally, the concept of closing speed and relative velocity is discussed, with the closing speed being able to exceed the speed of light while the relative velocity cannot.
  • #1
Ned Stark
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Homework Statement



Andrew is at rest in frame S and observes Bob moving to the right (frame S0 is
bobs rest frame) with speed v. On the ground, a distance L to the right of Andrew, is a lamp.
At the instant that bob passes Andrew (as observed in frame S), the lamp emits a flash of light

At what time (in frame S0) does the light reach bob?

Homework Equations



Δt'=γΔt
Δx'=(1/γ)Δx
γ=1/sqrt(1-(v/c)^2)

The Attempt at a Solution



Ive tried this problem using two methods, though I am not sure which one is correct, if any.
---------------------------
attempt 1)

let the instant that bob passes Andrew occur at t=0 and x=0

in frame S, bob receives the light at t = L/(v + c), but bobs clock runs slower by a factor of gamma

so in S0, bob receives the light at t'=γ*L/(v + c).

But wouldn't this imply that in bobs frame, the flash moves at velocity v+c? which violates the postulate that the speed of light is the same in any frame.

attempt 2)

in bobs frame, the lamp is moving towards him at speed v, so the distance to the lamp in frame S0 is contracted to L'=(1/γ)*L.

and in S0 the flash travels at speed c, so in S0, the flash reaches bob at time t'= L/(c*γ)


------------

i am leaning towards attempt 2, however in bobs frame, would the flash of light occur before bob passes andrew?
 
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  • #2
Ned Stark said:
attempt 1)

let the instant that bob passes Andrew occur at t=0 and x=0

in frame S, bob receives the light at t = L/(v + c), but bobs clock runs slower by a factor of gamma

so in S0, bob receives the light at t'=γ*L/(v + c).
Sounds good to me.

But wouldn't this imply that in bobs frame, the flash moves at velocity v+c? which violates the postulate that the speed of light is the same in any frame.
No. Why would you think that?

attempt 2)

in bobs frame, the lamp is moving towards him at speed v, so the distance to the lamp in frame S0 is contracted to L'=(1/γ)*L.

and in S0 the flash travels at speed c, so in S0, the flash reaches bob at time t'= L/(c*γ)
This attempt fails because in Bob's frame the light does not flash when Andrew passes Bob. You neglected the relativity of simultaneity.

Attempt 1 wins!
 
  • #3
Is it correct to say that in andrews frame, the relative velocity between the flash and bob is c+v?

That seems kinda funky.

But i do get what your saying about relativity of simultinaity. I drew a Minkowski diagram for bobs frame, and sure enough, in bobs frame the lamp does not flash at the same time as when bob passes andrew.
 
  • #4
Ned Stark said:
Is it correct to say that in andrews frame, the relative velocity between the flash and bob is c+v?

That seems kinda funky

actually It doesn't seem to funky now that I've thought about it some more. the important thing is that is bobs inertial frame, the speed of light relative to him is c
 
  • #5
Ned Stark said:
actually It doesn't seem to funky now that I've thought about it some more. the important thing is that is bobs inertial frame, the speed of light relative to him is c
Good! Looks like you figured it out.

The rate at which Bob and the flash approach each other as seen in Andrew's frame is often called the closing speed to distinguish it from relative velocity, which means something different. The closing speed of two objects can be greater than c, since it's not really the speed of anything. But the relative velocity of two objects can never exceed c.
 

FAQ: How Does Light Reach Bob in Special Relativity?

What is special relativity?

Special relativity is a theory developed by Albert Einstein in 1905 that describes how objects move in relation to each other at high speeds. It is based on two main principles: the laws of physics are the same for all observers in uniform motion, and the speed of light is constant in all frames of reference.

What is the difference between special relativity and general relativity?

Special relativity deals with the effects of motion on objects in the absence of gravity, while general relativity includes the effects of gravity in addition to motion. Special relativity is a special case of general relativity that applies to situations where gravity is not a significant factor.

How does special relativity affect time and space?

Special relativity introduces the concept of time dilation, where time appears to pass slower for objects moving at high speeds. It also shows that space and time are intertwined and can be distorted by gravity and motion.

What is the famous equation in special relativity?

The most famous equation in special relativity is E=mc^2, which relates energy (E) and mass (m) to the speed of light (c). It shows that mass and energy are equivalent and can be converted into each other.

How is special relativity applied in everyday life?

Special relativity has many practical applications, including GPS technology, particle accelerators, and nuclear energy. It also helps us understand the behavior of objects at high speeds, such as in space travel and the effects of near-light speed travel on astronauts.

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