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eidyllion
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Homework Statement
Suppose that you make careful observations of a pendulum on the surface of the Earth. You then move to Mars, where g is about 40% of the value on the surface of the Earth. How does the period of the pendulum on Mars compare with the period of the pendulum on Earth The period on Mars is _____ the period on Earth.The answer is B) Larger by a factor of 1/sqrt(0.4) than
Homework Equations
Angular frequency: ω= sqrt(g/L) = 2∏/T
This was achieved because I know that ω=2π/T and that T=2π*sqrt(L/g)
The Attempt at a Solution
My teacher's solution says:
T=2∏*sqrt(4g)
T is g^(-1/2)
so as g decreases→T increases
I don't understand his solution. Where does sqrt(4g) come from and why does that mean T is g^(-1/2)