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Babylady247
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Unpolarized light from an incandescent lamp has an intensity 176 Cd as measured by a light meter. What is the intensity reading on the meter when two ideal are inserted between the bulb and the meter with their axis of polarization making an angle of θ = 40.0° relative to each other? Express your answer in Cd.
am having some trouble with this problem. Here's what I have so far:
Known info:
Io=28 Cd
Theta= 6o
There are two polarizers, so theta1=6 and theta2=6
Equations:
I= Io/2
Malus' Law: I= Iocos^2theta
Work:
I used this to try and solve and it is wrong...
I = 28/2
I=14
Then
I = 28(cos6)^2 which = 27.7 (at theta1)
but there are two polarizers so 27.7 becomes the new Io for theta2
I=27.7(cos6)^2 which =27.4
So you add them right? 27.7+27.4 which = 55.1?
Where am I getting confused?
am having some trouble with this problem. Here's what I have so far:
Known info:
Io=28 Cd
Theta= 6o
There are two polarizers, so theta1=6 and theta2=6
Equations:
I= Io/2
Malus' Law: I= Iocos^2theta
Work:
I used this to try and solve and it is wrong...
I = 28/2
I=14
Then
I = 28(cos6)^2 which = 27.7 (at theta1)
but there are two polarizers so 27.7 becomes the new Io for theta2
I=27.7(cos6)^2 which =27.4
So you add them right? 27.7+27.4 which = 55.1?
Where am I getting confused?