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joeeykn245
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Homework Statement
Three identical resistors are connected in parralel. The equivalent resistance increases by 700 ohm when one resistor is removed and connected in series with the remaining two, which are still in parrallel. Find resistance of each resistor
Rt1 + 700ohms = Rt2
Homework Equations
(1/Rt) = (1/R1) + (1/R2) ... For a parallel Circuit
Rt = R1 + R2 ... For a series Circuit
The Attempt at a Solution
First, we made an equation for the initial parallel circuit
RT1 +700 = RT2
1/Rt1 =1/R + 1/R +1/R
1/Rt1=3/R
1/Rt = 3/R
R = 3Rt for later substitution
RT1 +700 = RT2
1/Rt1 =1/R + 1/R +1/R
1/Rt1=3/R
For the combination circuit..
RT2 = 2/R + R
We substituted the RT1 and RT2 into R's
RT1 +700 = RT2
R/3 + 700 = R/2 + R
After plugging it in, we get 600 for R. Is this correct?