- #1
kirby2
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A point charge 6.50 nC is at the center of a cube with sides of length 0.260 m.
PART A: What is the electric flux through the surface of the cube?
PART B: What is the electric flux through one of the six faces of the cube?
ATTEMPT:
A)
Total flux enclosed by the cube = Q / eo
6.5E-9/8.85 x 10^-12= 734.5
B)
flux through one of the six faces is
= Q / 6 eo
so 734.5/6 = 122.4
with the exception of units, are these right? i think I'm doing it wrong because i didn't use the side length in any of the calculations.
PART A: What is the electric flux through the surface of the cube?
PART B: What is the electric flux through one of the six faces of the cube?
ATTEMPT:
A)
Total flux enclosed by the cube = Q / eo
6.5E-9/8.85 x 10^-12= 734.5
B)
flux through one of the six faces is
= Q / 6 eo
so 734.5/6 = 122.4
with the exception of units, are these right? i think I'm doing it wrong because i didn't use the side length in any of the calculations.