How Does Spin Angular Momentum Influence Magnetic Dipole Energy in a Field?

[bon]

Homework Statement

A molecule possessing a magnetic dipole moment has squared spin angular momentum 3/4 h bar. give an expression for the energy of the molecule when it is stationary in a magnetic field of flux density B.


Write down the partition function Z.

Homework Equations

The Attempt at a Solution

So i know that E = -m.B but what has squared spin angular mom got to do with it?

Also how to I write down the partition function!?

 

[anathema]

Hello,

The squared spin angular momentum is related to the magnetic dipole moment through the equation μ = g√(s(s+1))μB, where μB is the Bohr magneton and g is the gyromagnetic ratio. This means that the energy of the molecule can be expressed as E = -μB B, where B is the magnetic field.

To write down the partition function, we can use the formula Z = ∑e^(-Ei/kT), where Ei is the energy of the i-th state and k is the Boltzmann constant. In this case, we only have one state with energy E = -μB B, so the partition function would be Z = e^(-μB B/kT). I hope this helps!