How Does Spin Behavior Change in a Rotating Magnetic Field?

In summary, the Hamiltonian of a spin $1/2$ in a magnetic field is given by \mathcal{H}=h(t)\cdot S, where the magnetic field is of the size |h(t)|=\Omega_0 and it is rotating on XY plan with angular velocity \omega, so the angle it is forming with X axis after time t is \varphi = \omega t. To solve this question, we can use the convention that the Hamiltonian of a spin in a rotating system is \tilde{\mathcal{H}}=\mathcal{H}-\omega S_z. We can find the angle of inflection \theta_0 in which the spin should be prepared in order to follow a
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guyafe
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Homework Statement


A question given by my professor. Already solved three section and need help in other two. Please advice:
The Hamiltonian of a spin $1/2$ in a magnetic field is given by [itex]\mathcal{H}=h(t)\cdot S[/itex], where the magnetic field is of the size [itex]|h(t)|=\Omega_0[/itex] and it is rotating on [itex]XY[/itex] plan with angular velocity [itex]\omega[/itex], so the angle it is forming with [itex]X[/itex] axis after time [itex]t[/itex] is [itex]\varphi = \omega t[/itex].
In order to solve this question you may use the convention that the Hamiltonian of a spin in a rotating system is [itex]\tilde{\mathcal{H}}=\mathcal{H}-\omega S_z[/itex].

(1) Find the angle of inflection [itex]\theta_0[/itex] in which you have to prepare the spin in order for it to follow in a constant angle after the rotating field.

Homework Equations


Convention given in the description

The Attempt at a Solution


Already solved:
In the rotating system we can assume without any lost of generality that the magnetic field is always on the [itex]X[/itex] axis direction. Using this and the previous convention we get a new Hamiltonian: [itex]\mathcal{H}=\Omega_0 S_x-\omega S_z[/itex].
We can consider this as a Hamiltonian of a system with an effective magnetic field [itex]\vec{B}=(\Omega_0,0,\omega)[/itex].
If we want the magnetic field to stay constant in this system and not precssitate, we need to prepare it in that direction: [itex]\theta=\arctan\frac{\omega}{\Omega_0}[/itex]

Homework Statement


At time zero you prepare the spin in [itex]X[/itex] direction, and let the spin rotate half a circle.
(2) What is the final direction of the spin in the limit [itex]\omega \to 0[/itex]?

Homework Equations


None

The Attempt at a Solution


Already solved:
Using an educated guess, we can say that if the magnetic field is rotating "slowly enough", the spin will follow it and end the rotation in the same direction the field does: [itex]-\hat{x}[/itex].

Homework Statement


(3) What is the maximal angular error [itex]\Delta \theta[/itex] from the previous section if [itex]\omega[/itex] is finite?

Homework Equations


None

The Attempt at a Solution


Sorry, had no idea how to approach this.

Homework Statement


(4) Which values of [itex]\omega[/itex] give zero angular error?

Homework Equations


None

The Attempt at a Solution


Sorry, had no idea ho to solve this

Homework Statement


(5) What is the final direction of the spin in the limit [itex]\omega \to \infty[/itex]?

Homework Equations


None

The Attempt at a Solution


Already solved:
Another educated guess: Now the field is rotating so fast so the spin won't have time to follow it and it will stay in its position: [itex]+\hat{x}[/itex].
 
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  • #2


Hi there,

It seems like you have already made some progress on this problem, so I will try to provide some additional guidance for the remaining questions.

For (3), we can use the fact that the spin will follow the magnetic field as long as the field rotates slowly enough. This means that there will be some maximum angular error that the spin can have in following the field. Can you think of a way to calculate this maximum error using the given information?

For (4), we are looking for values of \omega that will give zero angular error. In other words, we want to find the values of \omega that will make the spin follow the magnetic field perfectly. Can you think of a way to determine these values by using the given information?

For (5), you have already made an educated guess that the spin will stay in its original position (+\hat{x}) in the limit of \omega \to \infty. Can you think of a way to prove this using the given information and possibly some mathematical reasoning?
 

FAQ: How Does Spin Behavior Change in a Rotating Magnetic Field?

What is the concept of "spin half" in rotating field?

The concept of "spin half" refers to the intrinsic angular momentum of a quantum particle, such as an electron, which can only have two possible values (up or down) regardless of its energy or position. This spin half can be influenced by an external magnetic field, causing the particle to either align with or against the field's direction.

How does spin half behave in a rotating field?

In a rotating field, the spin half of a particle will precess around the axis of rotation, much like a spinning top. The direction and speed of this precession are determined by the strength and orientation of the field, as well as the properties of the particle.

What is the significance of spin half in rotating field for quantum mechanics?

The concept of spin half in rotating field plays a crucial role in quantum mechanics, as it is a fundamental property of particles and can be used to explain many phenomena, such as magnetism and the behavior of atoms. It also helps to explain the "spin-statistics" theorem, which states that particles with half-integer spin (such as electrons) must obey the Pauli exclusion principle.

Can spin half in rotating field be observed in everyday life?

Yes, spin half in rotating field can be observed in everyday life. For example, magnetic resonance imaging (MRI) machines use the precession of spin half particles in a magnetic field to create detailed images of the human body.

How is spin half in rotating field related to quantum computing?

In quantum computing, the concept of spin half in rotating field is utilized to store and manipulate information in quantum bits (qubits). By controlling the spin states of qubits, quantum computers can perform calculations much faster and more efficiently than classical computers, making use of the principles of quantum mechanics.

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