- #1
jabbie3
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Homework Statement
A simple pendulum uses a steel wire as the string. The length of this wire is 1.4 m at room temperature. If the temperature is increased by 11.9 degrees C, the length of the wire increases by 1.69 mm . What is the change in period of the pendulum?
Homework Equations
T=2pi*[tex]\sqrt{L/g}[/tex]
The Attempt at a Solution
Lfinal=1.4+.00169=1.40169m
Linitial=1.4m
g=9.8 m/s2
[tex]\Delta[/tex]T=Tfinal-Tinitial
=2pi*[tex]\sqrt{1.40169/9.8}[/tex]-2pi*[tex]\sqrt{1.4/9.8}[/tex]
=2.376253765-2.374820823=.0014329416 s
This is wrong :(. What am I doing wrong?