How Does the Displacement Equation Calculate Position Changes in Physics?

The displacement in this equation refers to the change in position from the initial position, not the physical size of the body. The length of the body is irrelevant in this context.In summary, displacement in the kinematic equation ##x=x_0+v_0 t + \frac{1}{2} at^2## refers to the change in position from the initial position, not the physical size of the body. The length of the body is irrelevant.
  • #1
-Physician
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We can have the velocity as v1 or v2 , time also, but In some cases i see it in displacement for e.x
##x=x_0+v_0 t + \frac{1}{2} at^2##, how can it be displacement 1 , displacement 2, can some one explain? Is it the displacement of the body 1, and displacement of the body 2 or what?
 
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  • #2
-Physician said:
We can have the velocity as v1 or v2 , time also, but In some cases i see it in displacement for e.x
##x=x_0+v_0 t + \frac{1}{2} at^2##, how can it be displacement 1 , displacement 2, can some one explain? Is it the displacement of the body 1, and displacement of the body 2 or what?
In that version of the kinematic equation, x0 is the initial position (at time t = 0), v0 the initial velocity, and x is the position at time t.
 
  • #3
Wouldn't that be the length of the body, like if the length of the body is 5m and distance 10m, the displacement would be 5m?
 
  • #4
-Physician said:
Wouldn't that be the length of the body, like if the length of the body is 5m and distance 10m, the displacement would be 5m?
No. Kinematics describes the movement of a body, not its dimensions.
 
  • #5


The equation you have provided is known as the displacement equation, which represents the position of an object at a given time. The two displacements mentioned, x1 and x2, refer to the initial displacement (x0) and the final displacement (x) respectively.

The equation tells us that the final displacement (x) is equal to the initial displacement (x0) plus the product of initial velocity (v0) and time (t), plus half the product of acceleration (a) and the square of time (t^2). This equation is often used to calculate the displacement of an object undergoing constant acceleration.

To clarify, displacement 1 and displacement 2 do not refer to different bodies. They are simply different positions of the same object, with displacement 1 being the initial position and displacement 2 being the final position. This equation allows us to calculate the displacement of an object at any given time, given its initial conditions (x0, v0, and a).

I hope this explanation helps to clarify the concept of displacement and how it relates to the equation you provided. If you have any further questions, please do not hesitate to ask.
 

FAQ: How Does the Displacement Equation Calculate Position Changes in Physics?

What is displacement?

Displacement is a physical quantity that measures the shortest distance and direction between two points. It is usually represented by the symbol "d" and measured in units of meters (m).

How is displacement different from distance?

Distance is a scalar quantity that measures the total length traveled by an object, while displacement is a vector quantity that measures the change in position of the object from its starting point to its ending point.

Can displacement be negative?

Yes, displacement can be negative. This occurs when an object moves in the opposite direction of its initial position, resulting in a negative value for displacement.

How is displacement calculated?

Displacement is calculated by subtracting the initial position from the final position, taking into account the direction of movement. The formula for displacement is: d = xf - xi, where xf is the final position and xi is the initial position.

What is the difference between displacement and position?

Position refers to the location of an object in space, while displacement refers to the change in position of the object. Displacement takes into account both the distance and direction of movement, while position only indicates the location of the object.

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