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Homework Statement
A square aperture with a side of length 0.5 mm is illuminated with light of wavelength 550 nm. At what distance from the aperture would the Fraunhofer diffraction pattern have a central maximum with a width also equal to 0.5 mm? What can you say about the Fraunhofer condition under these circumstances?
Homework Equations
W2 / Lλ << 1
where
W : aperture or slit size
L : distance from aperture
λ : wavelength
3. The Attempt at a Solution
0.5mm = 0.0005m
550 nm = 5.5*10-7m
L = W2 / λ
= (0.0005m)2 / 5.5*10-7m
= 45 cm - distance at which Fraunhofer diffraction pattern is observed
I'm a bit lost with this question / Fraunhofer diffraction. I think I may have used the wrong equation maybe. Any help would be much appreciated.