- #1
daudaudaudau
- 302
- 0
http://en.wikipedia.org/wiki/Mean_value_theorem#First_mean_value_theorem_for_integration"
Take a look at the Wikipedia proof. Now, wouldn't it be easier to prove it like this:
The ordinary mean value theorem says that
[tex]
G(b)-G(a)=(b-a)G'(\xi)
[/tex]
And the fundamental theorem of calculus says that
[tex]
G(b)-G(a)=\int_a^b G'(x)dx
[/tex]
So the conclusion is
[tex]
\int_a^b G'(x)dx=(b-a)G'(\xi)
[/tex]
Take a look at the Wikipedia proof. Now, wouldn't it be easier to prove it like this:
The ordinary mean value theorem says that
[tex]
G(b)-G(a)=(b-a)G'(\xi)
[/tex]
And the fundamental theorem of calculus says that
[tex]
G(b)-G(a)=\int_a^b G'(x)dx
[/tex]
So the conclusion is
[tex]
\int_a^b G'(x)dx=(b-a)G'(\xi)
[/tex]
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