- #1
BigJon
- 24
- 0
∞
Ʃ 1/(n(n+8))
n=1
So i used partial fractions and got (1/8)/(n) - (1/8)/(n+8)
From there i pulled out the 1/8 so now my equation is
∞
(1/8) Ʃ (1/n)-(1/(n+8))
n=1
So from here do i just start doing like s1= (1/8)(1-1/9), s2=(1/8)(1/2-1/10)
to find a value it converges to?
Ʃ 1/(n(n+8))
n=1
So i used partial fractions and got (1/8)/(n) - (1/8)/(n+8)
From there i pulled out the 1/8 so now my equation is
∞
(1/8) Ʃ (1/n)-(1/(n+8))
n=1
So from here do i just start doing like s1= (1/8)(1-1/9), s2=(1/8)(1/2-1/10)
to find a value it converges to?