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Homework Statement
Well, I did get an answer to this, but I don't think I did it right. It kinda seems wrong to me, so I wanted a second opinion :)
At 25 m below the surface of the sea (Density = 1025 kg/m^3), where the temperature is 5 degrees Celsius, a diver exhales an air bubble having a volume of 1 cm^3. If the surface temp of the sea is 20 degrees Celsius, what is the volume of the bubble just before it breaks the surface?
Homework Equations
Ideal gas: PV = nRT
P = Po + (DENSITY)gh ??Not sure if I should use this??
The Attempt at a Solution
P = Po + Density(g)(h) = 1.013 x 10^5 Pa + (1025)(9.81)(25)
P = 3.5 x 10^5 Pa (This seems fairly logical to me... kinda? But I'm not very logical :P)
Under the sea
(3.5 x 10^5)(0.01 m^3) = n(3.814)(278 degrees K)
n = 3.3
At surface
(1.013 x 10^5)(V) = (3.3)(3.814)(293)
V = 0.036 m^3, or 3.6 cm^3... that's fairly reasonable, isn't it?? But I'm not sure if using the P = Po + density(g)(h) was all right when the height is below the sea like that ??