- #1
unsung-hero
- 13
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Homework Statement
Ok, so the height of the cylinder is 5.5 meters. The radius is 1 meters.
There is a hole, .5 meters from the bottom(5 meters from the top), its radius is .02 meters.
The question is how fast does water flow out, relative to time(this because the height of the water keeps dropping, so the flow rate decreases). [/B]
Thank You :)
Homework Equations
Am i doing it right?
If i am, can you please solve it(i can't quiet figure it out)?
Please give the rate of change of the flowrate(dflowrate/dt).
Also, rate of change of height(dh/dt).
[/B]
The Attempt at a Solution
Height = total volume - (integral sign) flowrate dt
flowrate = (cross sectional area * Velocity(
dflowrate/dt = (deritive of the expression above)[/B]