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Homework Statement
An airplane flies at 600km/h on a bearing of W38N while a wind of 75km/h from W25S is present.
Find the planes resultant velocity and direction
The Attempt at a Solution
So here's what I did:
The Airplane: x = 600cos142 = -472.8
y = 600sin142 = 369.39
The Wind: x = 75cos25 = 67.973
y = 75sin25 = 31.69
Sum of x: -472.8 + 67.973 = -404.827
Sum of y: 360.30 + 31.69 = 401.09
Resultant would be using pythagorean theorem:
this gives me 569.877
and the angle would be theta = tan1- (401/-494.877) = -44.734 degreesI think what I did is right (please correct if I am wrong) but I was wondering about my angle. The angle is not below the horizontal right? I just don't understand why its negative. If i were to change it to bearing form would i do... 90-44.734 = 45.26 degrees therefore on a bearing of N45.26W? Please clarify the solution I have found