How Far and Fast Does Tina Drive to Pass David?

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    Acceleration
In summary, acceleration is the rate of change of an object's velocity over time and is calculated by dividing the change in velocity by the time it took for that change to occur. Positive acceleration occurs when an object is increasing in speed, while negative acceleration occurs when an object is decreasing in speed. Acceleration is directly proportional to force according to Newton's Second Law of Motion. Some real-life examples of acceleration include a car speeding up or slowing down, a roller coaster going down a hill, a rocket taking off, and a person jumping off a diving board.
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mullets1200
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Homework Statement




David is driving at a steady 26.0m/s when he passes Tina who is sitting in her car at rest. Tina begins to accelerate at a stead 2.20 m/s2 at the instant when david passes.

Questions to answer:
1) How far does Tina drive before passing David?

2)What is her speed as she passes him?
 
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What about the rest of the question template? What have you tried? What do you know that is relevant to this problem?
 
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I would approach this problem by using the basic formula for acceleration, which is a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time. In this case, we are given the initial velocity of David (vi = 26.0m/s) and the acceleration of Tina (a = 2.20 m/s^2). We are also given that Tina starts accelerating at the instant when David passes her, so we can assume that their time is the same.

1) To answer the first question, we need to find the time it takes for Tina to catch up to David. We can do this by setting their final velocities equal to each other, since they will have the same final velocity when she passes him. So, we have 26.0m/s = 2.20m/s^2*t. Solving for t, we get t = 11.82 seconds. Now, we can use the formula d = vi*t + 1/2*a*t^2 to find the distance Tina travels before passing David. Plugging in the values, we get d = 26.0m/s * 11.82s + 1/2 * 2.20m/s^2 * (11.82s)^2 = 155.2m. Therefore, Tina will drive 155.2m before passing David.

2) To answer the second question, we can use the formula vf = vi + a*t to find Tina's final velocity when she passes David. Plugging in the values, we get vf = 26.0m/s + 2.20m/s^2 * 11.82s = 51.6m/s. So, Tina's speed as she passes David will be 51.6m/s.

In conclusion, using the basic formula for acceleration and understanding the given information, we can calculate the distance Tina drives before passing David and her speed at that moment. This problem showcases the relationship between velocity, acceleration, time, and distance, which are fundamental concepts in the study of motion.
 

FAQ: How Far and Fast Does Tina Drive to Pass David?

1. What is acceleration?

Acceleration is the rate of change of an object's velocity over time. It is a vector quantity, meaning it has both magnitude (speed) and direction.

2. How is acceleration calculated?

Acceleration is calculated by dividing the change in an object's velocity by the time it took for that change to occur. The formula for acceleration is a = (vf - vi) / t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

3. What is the difference between positive and negative acceleration?

Positive acceleration occurs when an object is increasing in speed, while negative acceleration (also known as deceleration) occurs when an object is decreasing in speed.

4. How does acceleration relate to force?

According to Newton's Second Law of Motion, the force applied to an object is directly proportional to its acceleration. This means that the greater the force applied, the greater the acceleration will be.

5. What are some real-life examples of acceleration?

Some examples of acceleration in everyday life include a car speeding up or slowing down, a roller coaster going down a hill, a rocket taking off, and a person jumping off a diving board.

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