- #1
Kennedy111
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Homework Statement
What is the distance between two charges of -5.00 C each if the force of electrostatic repulsion acting on them is 4.00 x 10^3 N?
q1 = -5.00 C
q2 = -5.00 C
Fe = 4.00 x 10^3
k = 8.99 x 10^9 Nm^2/C^2
Homework Equations
Fe = kq1q2/r^2
The Attempt at a Solution
I rearranged the equation above and got:
r = (sqrt) kq1q2/Fe
r = (sqrt) (8.99 x 10^9 Nm^2/C^2)(5.00 C)(5.00 C) / (4.00 x 10^3 N)
= 7495.832175 m
To three significant digits my answer would be 7.50 x 10^ 3 m