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The velocity of waves on a string is 92 m/s. If the frequency of standing waves is 475Hz, how far apart are two adjacent nodes?
W = Wavelenght
f = v/W
W = 92/475 = 0.194 m
At this stage, I thought the answer was sufficient. However, maybe it is because i don't udnerstand the question, but the book says the answer should be 0.097m. The only way I could achieve this was to:
L = W/2 = 0.194 / 2 = 0.097m
This should then be a first harmonic wave. I am wondering:
Isnt the distance bewteen two adjacent nodes simply the wavelenght?
Why should I divide it by 2, and when does the question imply it is talking about a first harmonic wave?
Thank you
W = Wavelenght
f = v/W
W = 92/475 = 0.194 m
At this stage, I thought the answer was sufficient. However, maybe it is because i don't udnerstand the question, but the book says the answer should be 0.097m. The only way I could achieve this was to:
L = W/2 = 0.194 / 2 = 0.097m
This should then be a first harmonic wave. I am wondering:
Isnt the distance bewteen two adjacent nodes simply the wavelenght?
Why should I divide it by 2, and when does the question imply it is talking about a first harmonic wave?
Thank you