- #1
confounded
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Homework Statement
A jetliner can fly 7.35 hours on a full load of fuel. Without any wind it flies at a speed of 3.42 x 10^2 m/s. The plane is to make a round-trip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a 43.3-m/s wind from the jet stream, which blows from west to east. What is the maximum distance (in kilometers) that the plane can travel due west and just be able to return home?
Homework Equations
I'm not sure, but I'm guessing this: d/s + d/s = overall time and... probably something else?
The Attempt at a Solution
Well, I assumed because the jet stream is traveling in the same direction as the plane in both directions (west and east) that 43.3 m/s would be added to 3.42 x 10^2 m/s for the speed of the plane going to and coming back. I also converted 7.35 hours to seconds. So I ended up with distance traveled west/385.3 + distance traveled east/385.3= 26,460 s. Afterward, I ended up with distance traveled west=10,195,038m-distance traveled east. Now I'm just completely lost/confused. I just started taking physics last week, so I'm pretty new at this and I probably did everything wrong. Please help!
(P.S. Should I make the distance traveled east negative, since it's going in the opposite direction?)