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physics_newb
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Stopping Distance Grade 11 Physics Help Needed -- URGENT!
Yatin was driving at 90.0km/h when he saw the light turn yellow at an intersection located 75.0m ahead. Yatin used 0.400s to make up his mind, and then braked at 5.00m/s2 until he stopped. What was his stopping distance? Did Yatin make the right decision? If not, what could he have done differently?
(ATTEMPT BELOW COPIED/PASTED FROM MS WORD EQUATION EDITOR [MY WORK])
v1=90.0km/h or 25.0m/s
a=-5.00/s/s
v2=0.00m/s
Step 1:
t=v1/a
t=25.0/5.00
t=5.00s
Step 2:
d after making decision=d-(v1*t)
d after making decision=75-(25*.04)
d after making decision=75-1
d after making decision=74.0m
Step 3:
stopping distance=dtotal-(a*t)
stopping distance=74m-(5*5)
stopping distance=74-25
stopping distance=49m
Therefore Yatin`s stopping distance is 49m
Yatin was driving at 90.0km/h when he saw the light turn yellow at an intersection located 75.0m ahead. Yatin used 0.400s to make up his mind, and then braked at 5.00m/s2 until he stopped. What was his stopping distance? Did Yatin make the right decision? If not, what could he have done differently?
(ATTEMPT BELOW COPIED/PASTED FROM MS WORD EQUATION EDITOR [MY WORK])
v1=90.0km/h or 25.0m/s
a=-5.00/s/s
v2=0.00m/s
Step 1:
t=v1/a
t=25.0/5.00
t=5.00s
Step 2:
d after making decision=d-(v1*t)
d after making decision=75-(25*.04)
d after making decision=75-1
d after making decision=74.0m
Step 3:
stopping distance=dtotal-(a*t)
stopping distance=74m-(5*5)
stopping distance=74-25
stopping distance=49m
Therefore Yatin`s stopping distance is 49m