Doraneli said:1. A boulder initially at rest rolls down a hill with an acceleration of 3.69m/s^2. If it accelerates for 7.72 seconds, how far will it move?
2. d=v0(initial velocity)t+.5at^2
3. d=(0)(7.72)+.5(-9.8)(3.27)^2
Where did the "-39.24" come from? And why the "+-" for the second term?-39.24+-52.4
-91.64m
Constant acceleration is the rate at which the velocity of an object changes over time, while the direction of the object's motion remains constant. It can be represented by the formula a = Δv/Δt, where a is the acceleration, Δv is the change in velocity, and Δt is the change in time.
Constant acceleration refers to a situation where the acceleration remains the same throughout the motion, while uniform acceleration refers to a situation where the acceleration is constant and remains the same in both magnitude and direction.
Constant acceleration is calculated using the formula a = Δv/Δt, where a is the acceleration, Δv is the change in velocity, and Δt is the change in time. In other words, it is the change in velocity divided by the change in time.
Some examples of constant acceleration include an object falling freely under the influence of gravity, a car accelerating at a constant rate, and a rocket launching into space. In all of these situations, the acceleration remains constant throughout the motion.
Constant acceleration causes an object's velocity to change at a constant rate. This means that the object's speed increases or decreases by the same amount every second. As a result, the object's motion becomes more predictable and easier to analyze.