- #1
ptpatil
- 6
- 0
[SOLVED] Snowball off of a roof
A snowball rolls off of a roof angled downwards at 40.0 degrees, it has an initial velocity of 7.00 m/s. The roof is 14.0m tall.
Find how far from the edge of the roof the snowball falls
I know that cos -40 x 7.00m/s is the horizontal velocity, and Vy initial is sin -40 x 7.00.
OK, this seemed like a ridiculously easy problem, but the thing is I keep getting a value of t that i just know isn't correct (my friend already solved it, but I'd rather understand what I'm doing wrong than just copy).
To find t (time), I used Y= Yo + Vy x t + 1/2gt^2
I put in the values and had the ground as 0m and inital Y as 14.0m.
I got this: 0=14m + (-4.49m/s x t) + (-4.9 m/s/s x t^2)
I solved for t and always get 1.29s as the possible root. My friend says its incorrect and it seems incorrect to me as well since that would mean the snow ball lands a hefty 7 meters away from the roof.
Help?
Homework Statement
A snowball rolls off of a roof angled downwards at 40.0 degrees, it has an initial velocity of 7.00 m/s. The roof is 14.0m tall.
Find how far from the edge of the roof the snowball falls
Homework Equations
I know that cos -40 x 7.00m/s is the horizontal velocity, and Vy initial is sin -40 x 7.00.
The Attempt at a Solution
OK, this seemed like a ridiculously easy problem, but the thing is I keep getting a value of t that i just know isn't correct (my friend already solved it, but I'd rather understand what I'm doing wrong than just copy).
To find t (time), I used Y= Yo + Vy x t + 1/2gt^2
I put in the values and had the ground as 0m and inital Y as 14.0m.
I got this: 0=14m + (-4.49m/s x t) + (-4.9 m/s/s x t^2)
I solved for t and always get 1.29s as the possible root. My friend says its incorrect and it seems incorrect to me as well since that would mean the snow ball lands a hefty 7 meters away from the roof.
Help?