How far does it move before coming to rest again?

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In summary, two people standing on a hovering platform exchange a 6.9 kg ball, causing the platform to recoil. The total mass of the platform and people is 128 kg and the question asks for the distance the platform moves before coming to rest. Through calculations and rounding for significant figures, the answer is determined to be 0.12m.
  • #1
ladolce
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Homework Statement




Two people are standing on a 2.3 m long platform, one at each end. The platform floats parallel to the ground on a cushion of air, like a hovercraft. One person throws a 6.9 kg ball to the other, who catches it. The ball travels nearly horizontally. Excluding the ball, the total mass of the platform and people is 128 kg. Because of the throw, this 128 kg mass recoils. How far does it move before coming to rest again?

Homework Equations





The Attempt at a Solution



i tried the problem by drawing a diagram i got 0.12m but that answer's not right, and i have no clue why!
 
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  • #2
Is this one of those on-line homework systems? Perhaps it didn't like you rounding off.
 
  • #3
Yeah it is, but it might just be the wrong answer..I don't know if I did it right. Is that around what you got?
 
  • #4
Tell me how you solved it.
 
  • #5
i got the x _center of mass and set them equal to each other.

and got 134.9kgx_b=294.4kg

so x_b=2.182

and so x_r=2.182-2.3=-0.118

i wonder if that would be a better answer than 0.12?
 
  • #6
Wow, ok, that answer was right. Rounding has gotten me into a lot of trouble haha.
 
  • #7
I would say since the problem gives you two significant figues as the smallest, the answer must be with two significant figures too.

2.3 m, 6.9 kg, 128 kg

The answer must be 0.12, not 0.118
 
  • #8
that's what i hadput first but it said that was wrong... :( then i tried the 3 digit sig figs one and that worked..it always like the 3 digit sigfig answers better haha...
 
  • #9
I should complain A LOT ;)

UNLESS it is given in the problem:

2.30 and 6.90
 
  • #10
haha...my uncle's from malawi. and yeah that has happened a lot of me and this bad system of online homework
 

FAQ: How far does it move before coming to rest again?

What is the definition of "coming to rest" in this context?

The term "coming to rest" refers to when an object's motion stops completely and it remains in a fixed position.

How is the distance traveled before coming to rest calculated?

The distance traveled before coming to rest can be calculated using the formula d = (v2 - u2) / (2a), where d is the distance, v is the final velocity, u is the initial velocity, and a is the acceleration.

Does the distance traveled before coming to rest depend on the initial velocity?

Yes, the distance traveled before coming to rest is directly proportional to the square of the initial velocity. This means that the higher the initial velocity, the greater the distance traveled before coming to rest.

How does the surface or medium affect the distance traveled before coming to rest?

The surface or medium can greatly affect the distance traveled before coming to rest. For example, a rough surface with high friction will cause an object to come to rest more quickly compared to a smooth surface with low friction.

Is the distance traveled before coming to rest the same for all objects?

No, the distance traveled before coming to rest can vary for different objects depending on their mass, shape, and the medium they are moving through. Objects with a higher mass will require more force to come to rest and may travel a greater distance before doing so.

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