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xstetsonx
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Sam (60 kg) takes off (from rest) up a 50 m high, 10° frictionless slope on his jet-powered skis. The skis have a thrust of 200 N. He keeps his skis tilted at 10° after becoming airborne, as shown in Figure P6.43. How far does Sam land from the base of the cliff?
a=F/m
I used 50/sin10 to get the length of the slope-287.94m. Then i calculated the f on the slope. 200N-mgsin10. then i use that to divided by the mass which gives 1.63 for a. after that i go the final velocity before it jump off. then i have no idea wat to do next
a=F/m
I used 50/sin10 to get the length of the slope-287.94m. Then i calculated the f on the slope. 200N-mgsin10. then i use that to divided by the mass which gives 1.63 for a. after that i go the final velocity before it jump off. then i have no idea wat to do next