How far does the canoe move during this process?

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In summary, the problem involves a woman standing in a canoe and walking from one end to the other. If we ignore resistance to motion of the canoe in the water, the canoe will move a distance of 1.29 m during this process. This is because the center of mass of the system (woman and canoe) does not move and the woman's position must be added to the center of mass to determine the distance moved by the canoe.
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[SOLVED] Center of Mass

Homework Statement



A 45.0-kg woman stands up in a 60.0-kg canoe of length 5.00 m. She walks from a point 1.00 m from one end to a point 1.00 m from the other end.

yf_Figure_8_44.jpg


If you ignore resistance to motion of the canoe in the water, how far does the canoe move during this process?


2. The attempt at a solution

So she is moving to the other side of the canoe.

What do they mean by "If you ignore resistance to motion of the canoe in the water, how far does the canoe move during this process?"

That the water does not move the canoe?

Ma = 45kg
Mb = 60kg

There is no applied external force, so velocity is constant..(is this right)

How do I proceed...

(MaX + MbX) / (Ma+Mb) for finding center of mass, so

45X + 60X / 105 ...
 
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  • #2
Right, you've answered one of your own questions. There's no applied external force, so we can forget about any outside forces on the system. You know the equation for the center of mass, so you want to find the initial center of mass of the system, the system being the lady and the canoe. Next you want to find the center of mass of the system after the lady has walked one meter from the end of the canoe. The difference in the two cm's is the distance the conoe moves, right? Don't forget that we assume the canoe is of uniform mass, in other words, we take its center of mass, not to be confused with the center of mass of the system, to be right in the middle of the canoe. Does this help?
 
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  • #3
Better to write (MaXa+MbXb)/(Ma+Mb) as center of mass, where a is woman and b is canoe. When the woman (and canoe) move to new positions Y, the new center of mass is (MaYa+MbYb)/(Ma+Mb). But since there is no force from the water, the center of mass doesn't move. Why? So those two centers of mass are equal. Subtract the two and get zero. What does this tell you about the relation between (Xa-Ya) and (Xb-Yb)?
 
  • #4
After simplifying I get that

MaXa+MbXb = MaYa+MbYb

this should mean that there was no movement in the center of mass.

I see, the rest was plug in the equation above. And solve for Yb, and since it's the center of mass, Ya (Position of person) must be added 1.5 for her to reach the other side of the canoe. :)
 
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  • #5


Hey is the answer to this problem 1.29 m? Sorry for the huge bump, I didn't want to post something that was already posted. I just need someone to confirm this please?
 

FAQ: How far does the canoe move during this process?

1. How is the distance the canoe moves calculated?

The distance the canoe moves is typically calculated by measuring the displacement of the canoe from its starting point to its end point. This can be done by using a measuring tape or ruler to measure the distance, or by using GPS technology to track the movement of the canoe.

2. What factors can affect the distance the canoe moves?

Several factors can affect the distance the canoe moves during a process, such as the force and direction of the current or wind, the paddling technique of the person in the canoe, and any obstacles or obstructions in the water.

3. How does the weight of the canoe impact its movement during the process?

The weight of the canoe can affect its movement during the process in a few ways. A heavier canoe may require more force to move, and may be more difficult to steer or maneuver. However, a heavier canoe can also be more stable and less affected by external factors like wind or currents.

4. Is the distance the canoe moves always the same during each process?

No, the distance the canoe moves can vary depending on the specific process and conditions. Factors like wind, current, and obstacles can impact the distance the canoe moves, and even small differences in paddling technique or strength can result in varying distances.

5. How is the distance the canoe moves related to the speed of the process?

The distance the canoe moves is directly related to the speed of the process. The faster the canoe moves, the greater the distance it will cover in a given amount of time. However, it's important to note that the speed of the process can also be affected by external factors like wind and current, which can impact the distance the canoe is able to travel.

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