How Far Should the Voltmeter Probe Be Placed to Read 195V?

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To determine the distance from the surface of a charged insulating cylinder for a voltmeter to read 195V, the relevant equation is V=(λ/2πε₀)ln(R/r). The linear charge density (λ) is given as 16.0 nC/m, and the challenge lies in correctly identifying the relationship between the probe distances R and r. The misunderstanding arises from not accounting for the reference point; if R is measured from the cylinder's central axis, the distance r must be adjusted accordingly to reflect the distance from the surface. Clarifying this relationship is essential for solving the problem accurately. Understanding the geometry of the setup is crucial for finding the correct value of r.
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Homework Statement
A very long insulating cylinder of charge of radius 2.70cm carries a uniform linear density of 16.0 nC/m

Question: If you put one probe of a voltmeter at the surface, how far from the surface must the other probe be placed so that the voltmeter reads 195 ?


Relevant equations: The relevant equation for this problem is V=(lamda/2*pi*epsilon nought)*ln(R/r)



The attempt at a solution: For this problem I am trying to find little r in the above equation. 'Lambda' is given in the problem statement as (16*10^-9). To find little r, I first got the ln() function by itself by dividing each side of the equation by 'lambda/...' To save time I have denoted that function by A. So V/A=ln(R/r). I then took the exponential of each side to get ride of the ln() and I am left with r=R/[e^(V/A)]. I do not understand why this is not correct could someone please help me out. Thank you very much
 
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Be careful about the reference point. If R and r are measured from the central axis of the cylinder, and one is being asked about the distance x from the surface, which is at R, then what is the relationship between r and x?
 

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