- #1
JimRaynor
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Homework Statement
2. Two students are playing catch. The first student throws the ball with an initial speed of 25.0 m/s at an angle of 30.0° above horizontal. The ball is 1.20 meters above the ground when it leaves her hand. The second student must accelerate at a rate of 0.750 m/s2 in order to catch the ball when it is 0.80 meters above the ground. How far away from the first student was the second student initially
if she started to run at the same time that the first student let go of the ball?
Homework Equations
x = xo + v(o)t
y = yo + .5(Voy + Vy)t
y = yo + Voyt + .5at^2
Vy = Voy + ayt
Vy^2 = Voy^2 + 2a(y-yo)
The Attempt at a Solution
I drew a picture of what I have and don't have, and i know the Vox and Voy, but I am lost at how to apply the 7.50m/s^2 accleration into the problem. I am pretty lost atm, and some help is appreciated