- #1
PinkFly
- 1
- 0
1. Determine the distance it takes for a 25 kg box to stop sliding if it has a speed of 12m/s on a surface with a coefficient of friction of 0.15.
2. W=F*d
Coefficient of friction = Force of friction/Normal Force
Kinetic energy = 1/2*m*v^2
3. With the mass and the coefficient of friction, I got the force of friction.
With the mass and velocity, I got the kinetic energy.
Then I divided the Kinetic energy by the force of friction because the Newton's would cancel out and I would be left with meters.
Is this the right solution? I checked the answer in the back and it is correct but I'm not sure if this was just a coincidence.
2. W=F*d
Coefficient of friction = Force of friction/Normal Force
Kinetic energy = 1/2*m*v^2
3. With the mass and the coefficient of friction, I got the force of friction.
With the mass and velocity, I got the kinetic energy.
Then I divided the Kinetic energy by the force of friction because the Newton's would cancel out and I would be left with meters.
Is this the right solution? I checked the answer in the back and it is correct but I'm not sure if this was just a coincidence.