How Far Will a Box Slide Before Stopping on a Frictional Surface?

In summary, to determine the distance it takes for a 25 kg box to stop sliding with a speed of 12m/s on a surface with a coefficient of friction of 0.15, you need to use the formula W=Fd and the relationship between kinetic energy and force of friction. By dividing the kinetic energy by the force of friction, you can solve for the distance the box travels. This solution was confirmed to be correct by checking the answer in the back, and it is not just a coincidence.
  • #1
PinkFly
1
0
1. Determine the distance it takes for a 25 kg box to stop sliding if it has a speed of 12m/s on a surface with a coefficient of friction of 0.15.



2. W=F*d
Coefficient of friction = Force of friction/Normal Force
Kinetic energy = 1/2*m*v^2




3. With the mass and the coefficient of friction, I got the force of friction.
With the mass and velocity, I got the kinetic energy.
Then I divided the Kinetic energy by the force of friction because the Newton's would cancel out and I would be left with meters.


Is this the right solution? I checked the answer in the back and it is correct but I'm not sure if this was just a coincidence.
 
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  • #2
The Kinetic Energy is equal to the work that the friction force must do to stop the box. Since W=Fd, the distance that box travels is d=W/F. So yes, you did it correctly.
 

FAQ: How Far Will a Box Slide Before Stopping on a Frictional Surface?

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