How Far Will a Rock Travel Horizontally from a Volcano When Ejected at an Angle?

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Rocks ejected from a volcano can reach speeds of up to 170 m/s and a maximum height of 3,220 meters above sea level when launched vertically. For a rock ejected at a 30-degree angle, the horizontal distance it travels can be calculated by separating the x and y components of its motion. The time of flight is determined using the vertical motion equation, factoring in initial velocity and gravitational acceleration. Users are struggling with calculations, particularly in determining the correct time of flight and horizontal distance, which leads to incorrect results. Accurate application of kinematic equations is essential for solving these projectile motion problems.
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1. I got the first part right but I cannot figure out how to do the second part! Help please! And thank you!

Volcanoes on the Earth eject rocks at speeds of up to 170 m/s. Consider a 1750 m high volcano which ejects rocks in all directions. What is the maximum height above sea level reached by rocks?
Answer: 3.22*10^3m

part B: Consider a rock ejected an angle of 30degrees. How far from the axis of the volcano (horizontally) will it strike the ocean?
 
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separate your x and y components

x:
v0x=170cos30
x=?
t= from y

y:
v0y =170sin30
a =-9.81m/s^2
y = -1750m
t =
solve for t using y=v0*t+(1/2)at^2
then plug t into your x component to get x

(make sure to keep your initial y velocity positive and your acceleration and y distance negative)
 
Hi, Iam currently working on a similar problem and I keep getting it wrong. I found t to equal 17.34s or 3.57s by using the quadratic formula i then took a time and plugged it back into the formula using all the x component numbers and got 2429.14m or 4084.41m both are wrong.

my volcano is 2000m high and rocks are shooting at 45 degree angle traveling at 170m/s.
thanks
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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