How Far Will the Glasses Land from the Stopped Bicycle?

In summary: This was very helpful. In summary, the glasses would be displaced by (-4.192 m) if they were behind the bike, and (+4.192 m) if they were head-on with the bike.
  • #1
Jpyhsics
84
2

Homework Statement


A m=77.39 kg person on a bike is riding at v0,b=11.83 m/s. Suddenly, he sees a child running across his path! He applies the brakes that provide a deceleration of a= -4.192 m/s2. His glasses were not attached properly to his face, so they fly away and land on the pavement. If the glasses are assumed to start their flight traveling horizontally at a height of h=1.354 m above the ground, how far will those glasses be from the place where the bicyclist stops? Express your answer as a displacement in metres from the bike so that if glasses are behind the bike, the distance is negative, and if the glasses are head, the distance is positive.

Homework Equations


v=d/t
y=y0 +v0yt+1/2at^2
x=x0+v0xt+1/2at^2

The Attempt at a Solution


Link to solution I have worked out so far: https://drive.google.com/open?id=1QcxacQxuqsWx3ZpsdPGLV2m-PMyYKp62
 
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  • #2
Jpyhsics said:

Homework Statement


A m=77.39 kg person on a bike is riding at v0,b=11.83 m/s. Suddenly, he sees a child running across his path! He applies the brakes that provide a deceleration of a= -4.192 m/s2. His glasses were not attached properly to his face, so they fly away and land on the pavement. If the glasses are assumed to start their flight traveling horizontally at a height of h=1.354 m above the ground, how far will those glasses be from the place where the bicyclist stops? Express your answer as a displacement in metres from the bike so that if glasses are behind the bike, the distance is negative, and if the glasses are head, the distance is positive.

Homework Equations


v=d/t
y=y0 +v0yt+1/2at^2
x=x0+v0xt+1/2at^2

The Attempt at a Solution


Link to solution I have worked out so far: https://drive.google.com/open?id=1QcxacQxuqsWx3ZpsdPGLV2m-PMyYKp62
Hello @Jpyhsics,

Welcome to PF! :welcome:

In the future, please type out your work rather than link to an image of it. Images are fine for charts, graphs, and any supplemental material, but per the forum rules, we like to have it actually typed into the original post. (It's fine to do both, by the way, if that adds clarity.)

Anyway, your calculations involving the glasses look good to me. But your formula for the bicycle has a mistake in it. It's missing a t in there somewhere, leading to an incorrect answer.

(Also, for what it's worth, you might want to think about using a different kinematics formula for your bicycle calculation. It will save you a step. :wink:)
 
  • #3
collinsmark said:
Hello @Jpyhsics,

Welcome to PF! :welcome:

In the future, please type out your work rather than link to an image of it. Images are fine for charts, graphs, and any supplemental material, but per the forum rules, we like to have it actually typed into the original post. (It's fine to do both, by the way, if that adds clarity.)

Anyway, your calculations involving the glasses look good to me. But your formula for the bicycle has a mistake in it. It's missing a t in there somewhere, leading to an incorrect answer.

(Also, for what it's worth, you might want to think about using a different kinematics formula for your bicycle calculation. It will save you a step. :wink:)

Thank you so much!
 
  • Like
Likes collinsmark

FAQ: How Far Will the Glasses Land from the Stopped Bicycle?

What is projectile motion?

Projectile motion refers to the motion of an object through the air, such as a ball being thrown or a bullet being fired. It is a combination of both horizontal and vertical motion due to the force of gravity.

How do you calculate the initial velocity of a projectile?

The initial velocity of a projectile can be calculated using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s^2), and t is the time. Rearranging the equation, the initial velocity (u) can be found by u = v - at.

What is the maximum height of a projectile?

The maximum height of a projectile occurs at the highest point of its trajectory, also known as the vertex. To calculate this height, you can use the equation h = (u^2 * sin^2θ) / 2g, where h is the maximum height, u is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity.

How does air resistance affect projectile motion?

Air resistance, also known as drag, can affect the trajectory of a projectile by slowing it down and altering its path. The force of air resistance increases as the speed of the projectile increases, causing it to eventually reach a terminal velocity where the force of air resistance is equal to the force of gravity.

Can projectile motion be applied to real-world situations?

Yes, projectile motion is a fundamental concept in physics and is used in various real-world situations, such as sports (e.g. throwing a ball), engineering (e.g. designing a catapult), and military applications (e.g. launching a missile). Understanding projectile motion can also help with predicting the trajectory of objects, such as satellites and spacecrafts.

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