- #1
Niaboc67
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A bacteria culture initially contains 2000 bacteria and doubles every half hour. The formula for the population is p(t)=2000 e^{kt} for some constant k. (You will need to find k to answer the following.)
Find the size of the baterial population after 40 minutes.
Find the size of the baterial population after 10 hours.
Soltn:
When t = 0.5 hour, p(t) = 4000, so we have
4000 = 2000e^(0.5k)
2 = e^(0.5k)
ln(2) = 0.5k
k = ln(2)/0.5 = 1.386294361
Where did 4000 part come from?
Thank you
Where
Find the size of the baterial population after 40 minutes.
Find the size of the baterial population after 10 hours.
Soltn:
When t = 0.5 hour, p(t) = 4000, so we have
4000 = 2000e^(0.5k)
2 = e^(0.5k)
ln(2) = 0.5k
k = ln(2)/0.5 = 1.386294361
Where did 4000 part come from?
Thank you
Where