How Fast Does a Ball Travel When Dropped from 5 Meters?

[hafiz ns]

Homework Statement

A ball is dropped from a height of 5meters
a) what is the velocity of the ball when it reaches the ground ? explain

Homework Equations

velocity = displacement /time

The Attempt at a Solution

the velocity is increasing due the gravitation of Earth (as 9.8m/s) the ball is at a height of 5meter
is there any factor related to this ?

 

[phinds]

What do you mean "is there any factor related to this?". That IS the factor you want to take into consideration. You have the starting height and you have the acceleration due to gravity. You don't need anything else. Do you understand the equation of ballistic motion in a gravitational field?

 

[Andrew Mason]

Homework Statement

A ball is dropped from a height of 5meters
a) what is the velocity of the ball when it reaches the ground ? explain

Homework Equations

velocity = displacement /time

The Attempt at a Solution

the velocity is increasing due the gravitation of Earth (as 9.8m/s) the ball is at a height of 5meter
is there any factor related to this ?

Welcome to PF hafiz ns.

There are several ways of approaching this: Using energy, you can determine the speed from the change in potential energy; By finding t first and finding average velocity from your equation (average velocity = displacement/time), then using the relationship between final and average velocities; You could also find t and use the relationship between acceleration, velocity and time.

AM

 

[physicsshiny]

hafiz, to answer your question: yes, there is a factor to do with the acceleration. So think about how acceleration affects the velocity of the ball with time.

 

[HalfLostAndSearching]

I can provide a more detailed explanation for the velocity of a ball dropped from a height of 5 meters. The velocity of the ball can be calculated using the equation v = √(2gh), where v is the velocity, g is the acceleration due to gravity (9.8 m/s²), and h is the height from which the ball is dropped. Therefore, the velocity of the ball when it reaches the ground can be calculated as v = √(2*9.8*5) = √(98) = 9.9 m/s. This means that the ball will be traveling at a speed of 9.9 m/s when it reaches the ground.

There are several factors that can affect the velocity of the ball as it falls. These include air resistance, the shape and size of the ball, and the density and composition of the air through which it is falling. For example, a larger and more aerodynamic ball will experience less air resistance and therefore have a higher velocity when it reaches the ground. Additionally, the acceleration due to gravity may vary slightly depending on the location and altitude where the ball is dropped.

In conclusion, the velocity of a ball dropped from a height of 5 meters can be calculated using the equation v = √(2gh) and will be approximately 9.9 m/s. Various factors such as air resistance and the characteristics of the ball can also affect the velocity of the ball as it falls.