How Fast Does a Bowling Ball Travel When It Falls Off a Table?

In summary, the task is to calculate the velocity of a 7.5kg bowling ball as it falls from a 1.0m high horizontal table, disregarding air resistance and using a gravity acceleration of 9.8m/s. The given horizontal velocity is 10m/s and the solution involves finding the vertical component through Pythagorean theorem and possibly giving its direction as well.
  • #1
Michael17
13
0
Bowling ball and table!

Can anyone please help me figure this one out;

A bowling ball of mass 7.5kg traveling at 10m/s rolls off a horizontal table 1.0 m high. Calculate the velocity of the ball as it reaches the floor, ignoring air resistance and having an acceleration due to gravity of 9.8m/s.
 
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  • #2


Michael17 said:
Can anyone please help me figure this one out;

A bowling ball of mass 7.5kg traveling at 10m/s rolls off a horizontal table 1.0 m high. Calculate the velocity of the ball as it reaches the floor, ignoring air resistance and having an acceleration due to gravity of 9.8m/s.
They gave you the horizontal component of velocity. They want you to find the vertical component and then combine the 2 like Pythagoras would to yield the answer for the magnitude of the |velocity| vector. Now they may also want you to give the direction. (That would be tan-1 of the ratio of the 2.)
 
  • #3


I would approach this problem by using the principles of Newton's laws of motion and the equations of motion to solve for the velocity of the bowling ball as it reaches the floor.

Firstly, we need to identify the known values in this problem. We know the mass of the bowling ball (7.5kg), its initial velocity (10m/s), the height of the table (1.0m), and the acceleration due to gravity (9.8m/s). Our goal is to find the final velocity of the ball as it reaches the floor.

Using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement, we can rearrange it to solve for v: v = √(u^2 + 2as).

Substituting the known values, we get v = √(10^2 + 2(9.8)(-1)). This gives us a final velocity of approximately 7.07m/s as the ball reaches the floor.

In conclusion, the velocity of the bowling ball as it reaches the floor is approximately 7.07m/s. This calculation is based on the assumption that there is no air resistance and the acceleration due to gravity is 9.8m/s. It is important to note that in real-life scenarios, there may be other factors that could affect the final velocity of the ball, such as air resistance or the surface of the table.
 

FAQ: How Fast Does a Bowling Ball Travel When It Falls Off a Table?

How much does a bowling ball weigh?

The weight of a bowling ball can vary, but the standard weight used in most bowling alleys is between 14-16 pounds.

What are bowling balls made of?

Bowling balls are typically made of a combination of materials, including polyester, urethane, or reactive resin. These materials give the ball its weight, durability, and ability to grip the lane.

What is the diameter of a bowling ball?

The diameter of a bowling ball is approximately 8.5 inches, or 21.6 centimeters. However, the exact size may vary slightly depending on the manufacturer and the weight of the ball.

How is a bowling ball measured for fit?

Bowling balls are typically measured using the span and circumference method. The span is the distance between the thumb and finger holes, while the circumference is the distance around the ball. These measurements are used to determine the best fit for the bowler's hand.

How do I choose the right bowling ball for my skill level?

The best way to choose a bowling ball is to consider your skill level, lane conditions, and personal preference. Beginners may want to start with a plastic or polyester ball, while more experienced bowlers may opt for a reactive resin ball. It's also important to consult with a professional or experienced bowler for personalized recommendations.

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