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lanvin
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Mars travels around the sun in 1.88 {Earth} yrs,in an approximately circular orbit with a radius of 2.28 * 10^8km.Determine
{a}The orbital speed of Mars {relative to the sun}Answer {a}:
period {T} = 1.88 * 365 *24 * 3600 sec , R = 2.28 * 10^8 * 10^2 = 2.28 * 10^11
d = 2 pie R ------> 2 * 3.14 * 2.28 * 10^11
V=d / T -------> { 2 * 3.14 * 2.28 * 10^11 } / { 1.88 * 365 *24 * 3600 }
=2.4 * 10^4m/sIs that correct?or do I use
acceleration of centripetal motion = (4)(pi^2)(r)(f^2)
then use the acceleration and find velocity in
V = √(acceleration x radius)
which method is correct? if any...
{a}The orbital speed of Mars {relative to the sun}Answer {a}:
period {T} = 1.88 * 365 *24 * 3600 sec , R = 2.28 * 10^8 * 10^2 = 2.28 * 10^11
d = 2 pie R ------> 2 * 3.14 * 2.28 * 10^11
V=d / T -------> { 2 * 3.14 * 2.28 * 10^11 } / { 1.88 * 365 *24 * 3600 }
=2.4 * 10^4m/sIs that correct?or do I use
acceleration of centripetal motion = (4)(pi^2)(r)(f^2)
then use the acceleration and find velocity in
V = √(acceleration x radius)
which method is correct? if any...
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