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shaunanana
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Homework Statement
When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^1.14=C, where C is a constant. Suppose that at a certain instant the volume is 600 cm^3 and the pressure is 80 kPa and is decreasing at a rate of 10 kPa/min. At what rate is the volume increasing at this instant?
Homework Equations
dP/dt=-10
we want dV/dt when V=600 and P=80
The Attempt at a Solution
V=(1.4 root)(C/P)
80(600)^1.4=C
C=620157
dV/dt=1/1.4(C/P)^-0.4((cp'-pc')/p^2)dP/dt
=1/1.4(C/P)^-0.4((c10-0)/p^2)(-10)
then i plugged in P=80 and C=620157 to get an answer of 192.5 cm^3/min which was wrong.
Can anyone show we where I went wrong and how to get the proper solution?
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