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kalupahana
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Free fall, problem, please help
A hoist is lifting a naturalist to the top of a cliff at 2.03 m/s vertically. The naturalist suddenly realizes she has left her pet rock behind. A friend picks it up and tosses it straight upward. If the naturalist is 2.50 m above her friend, what is the minimum initial speed the pet rock must have to reach the naturalist?
(consider gravitational acceleration as 10ms-2 & air resistance negligible)
s = ut + ½ at2
v= u + at
v2 = u2 + 2as
Here u is initial velocity & v is final velocity
The information of problem as follows
....The hoist......pet rock
u ....2.03....... ?
v...2.03....... ?
s ...2.5 + x......2.5 + x
t ...?....... ?
a...non.......-10
the both time & displacement should be equal
So the displacement of hoist
2.5 + x
The get minimum initial velocity the final velocity should be 0.
v = u + at
0 = u - 10t
t = u/10
the u is equal to
v2 = u2 + 2as
u2 = 20(2.5+x)
the displacement is equal to
s = ut + ½ at2
2.5 + x = ut - 5t2
from here i don't have any idea, please help me.
What is the time of hoist when pet rock reach
2.5 + x = 2.03t
t = (2.5 + x)/2.03
or
x = 2.03t
t = x/2.03
which one i should take
Homework Statement
A hoist is lifting a naturalist to the top of a cliff at 2.03 m/s vertically. The naturalist suddenly realizes she has left her pet rock behind. A friend picks it up and tosses it straight upward. If the naturalist is 2.50 m above her friend, what is the minimum initial speed the pet rock must have to reach the naturalist?
(consider gravitational acceleration as 10ms-2 & air resistance negligible)
Homework Equations
s = ut + ½ at2
v= u + at
v2 = u2 + 2as
Here u is initial velocity & v is final velocity
The Attempt at a Solution
The information of problem as follows
....The hoist......pet rock
u ....2.03....... ?
v...2.03....... ?
s ...2.5 + x......2.5 + x
t ...?....... ?
a...non.......-10
the both time & displacement should be equal
So the displacement of hoist
2.5 + x
The get minimum initial velocity the final velocity should be 0.
v = u + at
0 = u - 10t
t = u/10
the u is equal to
v2 = u2 + 2as
u2 = 20(2.5+x)
the displacement is equal to
s = ut + ½ at2
2.5 + x = ut - 5t2
from here i don't have any idea, please help me.
What is the time of hoist when pet rock reach
2.5 + x = 2.03t
t = (2.5 + x)/2.03
or
x = 2.03t
t = x/2.03
which one i should take